00:01
Hello student, here the internal diameter pi is 200 mm.
00:09
So, internal resistance ri equals to 100 mm and thickness is given as 50 mm.
00:20
So, outer radius r0 is ri plus p which is 150 mm.
00:29
Now, the expression for tangential stress at any radius x is sigma t equals to p ri square into r0 square minus ri square into 1 plus r0 square by x square.
01:01
Now, for the inner surface x equals to ri.
01:09
So, with this sigma t becomes p into, so for the inner surface sigma t becomes p into r0 square plus ri square divided by r0 square minus ri square equals to 5 into 150 square into 100 square divided by 150 square minus 100 square equals to 13 mega pascal.
01:58
So, this is at the inner surface but the i, i stands for inner.
02:08
Now, at the middle surface x equals to 125 mm.
02:18
So, sigma t becomes sigma t middle is 5 into 100 square divided by 150 square minus 100 square into 1 plus 150 square divided by 125 square, the unit of mega pascal.
02:47
So, this is equals to 9 .76 mega pascal.
02:57
Now, the outer surface x equals to r0 equals to 150 mm.
03:10
So, tangential stress at the outer surface equals to 2 into 5 into 100 square divided by 150 square minus 100 square...