The Stirling heat engine operates between 2 isotherms and 2...

The Stirling heat engine operates between 2 isotherms and 2 isochrones as in the accompanying figure P Isothermal processes B C 3Ti A D Ti Vi 2Vi V Consider n moles of a monatomic gas being taken around the cycle shown (a) (3 points) Find the energy transferred by heat for the isochoric process AB. Is heat added or removed along path AB? (b) (3 points) Find the energy transferred by heat for the isothermal process BC. Is heat added or removed along path BC? (c) (3 points) Find the energy transferred by heat for the isochoric process CD. Is heat added or removed along path CD? (d) (3 points) Find the energy transferred by heat for the isothermal process DA. Is heat added or removed along path DA? (e) (6 points) Using the first law of thermodynamics find the work done by the heat engine

Transcript

00:01 Hello everyone.

00:02 So in the question it is given that sterling's engine operates between two isotherm and isocones.

00:08 Okay.

00:09 So this two curves are isothermal and these are isocons.

00:18 Okay.

00:19 Now what do we mean by isocon? isocon means where the volume remains constant.

00:25 It does not change.

00:27 Okay.

00:28 So change in volume is zero.

00:29 That means isocone.

00:31 And isothermal means change in temperature is zero, okay? now we have to find the energy transferred by heat for isocone process ab, okay? so for this process we have to find the change in energy, okay? and what happens to the heat? heat is absorbed or it is removed along the path ab that we have to find, okay? so for isocone process we know that change in volume is equals to 0.

01:14 So if we find the work done, okay, it is p delta v.

01:23 So the work done is 0 joules in isocone.

01:28 Now by the first law of thermodynamics, okay, the change in input.

01:37 Internal energy is equals to heat minus the work done.

01:43 Now work done is zero over here.

01:46 So the change in internal energy is equals to heat that is added in the system.

01:56 So now how do we get to know that if heat is added or removed? so we will have to see the sign of q.

02:06 Okay so now q is equal to change in internal energy so the formula is given as m cv delta t okay so initially you can see that temperature is low okay you can see over here the temperature is low which is t1 and here it is 3 t okay so let us substitute that over here m cv 3 t minus t okay which gives us 2 mcv t okay so the heat is added over here as the internal energy increases okay so the heat added is to mcv t okay okay now we have to find for bc, okay? if heat is added or heat is removed that we have to find and we have to find the energy transferred by the heat for isothermal.

03:42 So now for isothermal, as temperature does not change, okay, so the internal energy remains constant...

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