00:01
Hello students given mass of glucose is 11 .7 grams and given mass of ethanol is 325 grams.
00:10
The temperature of solution is 78 .59 degrees celsius and temperature of pure ethanol given is 78 .35 degrees celsius.
00:22
Boiling point elevation constant is 1 .20 degrees celsius kg per mole.
00:28
The elevation in temperature on addition of glucose in ethanol is given as molar elevation constant multiplied by molality.
00:44
Elevation in boiling point is temperature of the solution minus temperature of pure ethanol equal to kb constant.
00:57
Molality is number of moles of the salute which is equal to given mass of the salute divided by molecular weight of the salute divided by mass of the solvent in kg.
01:18
So multiplying it by thousand.
01:22
To find out the molecular weight of the salute substituting the values, it becomes after solving the equation, to find out the value of molecular weight m2 comes out to be 180 grams.
01:41
This is the molecular weight of fructose.
01:49
To find out the molecular formula of fructose, writing down the percentage presents in grams, carbon is 40 grams, hydrogen is 6 .7 grams and oxygen is 53 .3 grams...