The sun radiates electromagnetic energy at the rate of 3.9×10 26W . Its radius is 6.96×10 8m. The intensity of sun light at the solar surface will be in ( m 2 W)
Added by Simon S.
Step 1
The power (P) radiated by the sun is given as 3.9×10^26 W. The area (A) of the sun can be calculated using the formula for the surface area of a sphere, which is 4πr^2, where r is the radius of the sun. So, A = 4π(6.96×10^8 m)^2 = 6.0877×10^18 m^2. Now, we Show more…
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The sun radiates electromagnetic energy at the rate of $3.9 \times 10^{26} \mathrm{~W}$. Its radius is $6.96 \times 10^{8} \mathrm{~m}$. The intensity of sun light at the solar surface will be (A) $1.4 \times 10^{4}$ (B) $2.8 \times 10^{5}$ (C) $4.2 \times 10^{6}$ (D) $5.6 \times 10^{7}$
The sun radiates electromagnetic energy at the rate of $3.9 \times 10^{26} \mathrm{~W}$. Its radius is $696 \times 10^{8} \mathrm{~m}$. The intensity of sunlight (in $\mathrm{Wm}^{-2}$ ) at the solar surface will be (a) $4.3 \times 10^{6}$ (b) $4.5 \times 10^{7}$ (c) $5.6 \times 10^{7}$ (d) $5.8 \times 10^{6}$
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Round 2
The surface of the Sun has a temperature of about 5800 $\mathrm{K}$ . The radius of the Sun is $6.96 \times 10^{8} \mathrm{m} .$ Calculate the total energy radiated by the Sun each second. Assume that the emissivity of the Sun is $0.965 .$
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