Question

The switch in FIGURE P34.80 has been open for a long time. It is closed at $t=0 \mathrm{s}$ a. After the switch has been closed for a long time, what is the current in the circuit? Call this current $I_{0}$. b. Find an expression for the current $I$ as a function of time. Write your expression in terms of $I_{0}, R,$ and $L$ c. Sketch a current-versus-time graph from $t=0$ s until the current is no longer changing.

          The switch in FIGURE P34.80 has been open for a long time. It is closed at $t=0 \mathrm{s}$
a. After the switch has been closed for a long time, what is the current in the circuit? Call this current $I_{0}$.
b. Find an expression for the current $I$ as a function of time. Write your expression in terms of $I_{0}, R,$ and $L$
c. Sketch a current-versus-time graph from $t=0$ s until the current is no longer changing.

Added by Alexis B.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Aparna Shakti

12/15/2021

Step 1

After the switch has been closed for a long time, the circuit will reach a steady state. In this state, the current will be constant and equal to $I_0$. This is because in a steady state, the inductor acts like a short circuit, allowing current to flow freely Show more…

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The switch in FIGURE P34.80 has been open for a long time. It is closed at $t=0 \mathrm{s}$ a. After the switch has been closed for a long time, what is the current in the circuit? Call this current $I_{0}$. b. Find an expression for the current $I$ as a function of time. Write your expression in terms of $I_{0}, R,$ and $L$ c. Sketch a current-versus-time graph from $t=0$ s until the current is no longer changing.