Question

The switch in the circuit shown in the figure below is opened at $t = 0$ s. Assume that $I_s = 4.4$ A. Answer the following questions: $i(t = 0)$ can be found as: Oa. 2.6 A Ob. 2.8 A Oc. 3 A Od. 3.2 A The current $i$ at $t = 70$ ms is: Oa. 1.896 A Ob. 2.296 A Oc. 2.496 A Od. 2.096 A The voltage $v$ at $t = 70$ ms is: Oa. 14.976 V Ob. 13.776 V Oc. 11.375 V Od. 12.576 V

          The switch in the circuit shown in the figure below is opened at $t = 0$ s.
Assume that $I_s = 4.4$ A. Answer the following questions:

$i(t = 0)$ can be found as:
Oa. 2.6 A
Ob. 2.8 A
Oc. 3 A
Od. 3.2 A

The current $i$ at $t = 70$ ms is:
Oa. 1.896 A
Ob. 2.296 A
Oc. 2.496 A
Od. 2.096 A

The voltage $v$ at $t = 70$ ms is:
Oa. 14.976 V
Ob. 13.776 V
Oc. 11.375 V
Od. 12.576 V

The switch in the circuit shown in the figure below is opened at t = 0 s.
Assume that Is = 4.4 A. Answer the following questions:

i(t = 0) can be found as:
Oa. 2.6 A
Ob. 2.8 A
Oc. 3 A
Od. 3.2 A

The current i at t = 70 ms is:
Oa. 1.896 A
Ob. 2.296 A
Oc. 2.496 A
Od. 2.096 A

The voltage v at t = 70 ms is:
Oa. 14.976 V
Ob. 13.776 V
Oc. 11.375 V
Od. 12.576 V

Added by Alexandra L.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Ronald Prasad

Step 1

This means that the inductor is disconnected from the circuit and the current through it will start to decrease. The current I(t=0) can be found using the formula for the current in an inductor when the switch is opened: I(t) = I(0) * e^(-t/τ) where I(t) is the Show more…

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The switch in the circuit shown in the figure below is opened at t=0s. Assume that I=4.4A. Answer the following questions: t=0 20V 12 20 0.5H I(t=0) can be found as: Oa. 2.6A Ob. 2.8A Oc. 3A Od. 3.2A The current I at t=70ms is: Oa. 1.896A Ob. 2.296A Oc. 2.496A Od. 2.096A The voltage V at t=70ms is: Oa. 14.976V Ob. 13.776V Oc. 11.375V Od. 12.576V