Question

The system in Figure is at 20°C. Compute the pressure at point A in lbf/ft² absolute. Oil, SG = 0.75 Water 5 in Pa = 15.0 lbf/in² A 10 in 6 in Water Mercury 2815.6 lbf/ft^2 2405.6 lbf/ft^2 670.6 lbf/ft^2 2867.6 lbf/ft^2

          The system in Figure is at 20°C. Compute the pressure at point A in lbf/ft² absolute.
Oil, SG = 0.75
Water
5 in
Pa = 15.0 lbf/in²
A
10 in
6 in
Water
Mercury
2815.6 lbf/ft^2
2405.6 lbf/ft^2
670.6 lbf/ft^2
2867.6 lbf/ft^2

Added by Luc-A W.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Sri K

09/29/2022

Step 1

0 lbf/in^2 to lbf/ft^2. 1 in = 0.0833 ft So, 15.0 lbf/in^2 = 15.0 lbf/in^2 * (0.0833 ft/in)^2 = 15.0 lbf/in^2 * 0.006944 ft^2/in^2 = 0.1042 lbf/ft^2 Show more…

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The system in Figure is at 20deg C. Compute the pressure at point A in lb(f)/(f)t^(2) absolute. 2815.6lb(f)/(f)t^(^(^())2) 2405.6lb(f)/(f)t^(^(^())2) 670.6lb(f)/(f)t^(^(^()))2 2867.6lb(f)/(f)t^(^(^())2) The system in Figure is at 20'C. Compute the pressure at point A in Ibf/ft2 absolute. Water Oil, SG = 0.75 Pa = 15.0 lbf/in2 5 in 10 in V 6 in Water Mercury O 2815.6 Ibf/ft^2 O2405.6 Ibf/ft^2 O 670.6 Ibf/ft^2 2867.6 Ibf/ft^2