Question

The system shown in the figure below has an acceleration of magnitude 0.56 m/s2, where m1 = 4.50 kg and m2 = 6.20 kg. Assume that the coefficient of kinetic friction between block and incline is the same for both inclines. m1 m2 35.0° 35.0° (a) Find the coefficient of kinetic friction. (b) Find the tension in the string.

          The system shown in the figure below has an acceleration of magnitude 0.56 m/s2, where m1 = 4.50 kg and m2 = 6.20 kg. Assume that the coefficient of kinetic friction between block and incline is the same for both inclines.
m1
m2
35.0°
35.0°
(a) Find the coefficient of kinetic friction.
(b) Find the tension in the string.
        
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The system shown in the figure below has an acceleration of magnitude 0.56 m/s2, where m1 = 4.50 kg and m2 = 6.20 kg. Assume that the coefficient of kinetic friction between block and incline is the same for both inclines.
m1
m2
35.0°
35.0°
(a) Find the coefficient of kinetic friction.
(b) Find the tension in the string.

Added by Gregorio V.

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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The system shown in the figure below has an acceleration of magnitude 0.56 m/s2, where m1 = 4.50 kg and m2 = 6.20 kg. Assume that the coefficient of kinetic friction between block and incline is the same for both inclines. (a) Find the coefficient of kinetic friction. (b) Find the tension in the string.
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Transcript

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00:01 Hello, here we have to solve the following problem.
00:02 The system shown in the task has acceleration of 0 .56 meters per square second and m1 is 4 and a half kilograms.
00:14 That m2 is 6 .20 kilograms.
00:21 And here we have to find a coefficient of kinetic friction first.
00:29 Let's do this.
00:30 So let's catch this system both slopes as a same.
00:34 And these slopes are 35 degrees each.
00:41 Now let's catch the forces acting on each block.
00:44 M2 is heavier and that's why m2 is moving downwards and its friction force is up the incline.
00:58 M1 is moving up and now we can write down second newton's low equation for each of those blocks...
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