Question

The table shown here lists the specific heat of several substances. Substance Specific heat J/g/°C water 4.18 ethyl alcohol 2.44 benzene 1.80 sulfuric acid 1.40 Which of the following statements are true? Select all that apply. ? View Available Hint(s) Benzene is more resistant to temperature change than sulfuric acid. More heat is required to raise the temperature of 1 g of water 1°C than to raise the temperature of 1 g of ethyl alcohol 1 °C. More heat is required to raise the temperature of 1 g of benzene 1°C than to raise the temperature of 1 g of water 1 °C. Sulfuric acid is less resistant to temperature change than water. Water has a high specific heat due to the hydrogen bonding between water molecules Ethyl alcohol likely exhibits more hydrogen bonding than water. Water is less resistant to temperature change than ethyl alcohol.

          The table shown here lists the specific heat of several substances.
Substance
Specific heat
J/g/°C
water
4.18
ethyl alcohol
2.44
benzene
1.80
sulfuric acid
1.40
Which of the following statements are true?
Select all that apply.
? View Available Hint(s)
Benzene is more resistant to temperature change than sulfuric acid.
More heat is required to raise the temperature of 1 g of water 1°C than to raise the temperature of 1 g of ethyl alcohol 1 °C.
More heat is required to raise the temperature of 1 g of benzene 1°C than to raise the temperature of 1 g of water 1 °C.
Sulfuric acid is less resistant to temperature change than water.
Water has a high specific heat due to the hydrogen bonding between water molecules
Ethyl alcohol likely exhibits more hydrogen bonding than water.
Water is less resistant to temperature change than ethyl alcohol.
        
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The table shown here lists the specific heat of several substances.
Substance
Specific heat
J/g/°C
water
4.18
ethyl alcohol
2.44
benzene
1.80
sulfuric acid
1.40
Which of the following statements are true?
Select all that apply.
? View Available Hint(s)
Benzene is more resistant to temperature change than sulfuric acid.
More heat is required to raise the temperature of 1 g of water 1°C than to raise the temperature of 1 g of ethyl alcohol 1 °C.
More heat is required to raise the temperature of 1 g of benzene 1°C than to raise the temperature of 1 g of water 1 °C.
Sulfuric acid is less resistant to temperature change than water.
Water has a high specific heat due to the hydrogen bonding between water molecules
Ethyl alcohol likely exhibits more hydrogen bonding than water.
Water is less resistant to temperature change than ethyl alcohol.

Added by Charles D.

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Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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The table shown here lists the specific heat of several substances. able[[Substance, able[[Specific heat],[(J)/(g)/deg C The table shown here lists the specific heat of several substances Substance Specific heat water 4.18 2.44 1.80 1.40 ethyl alcohol benzene sulfuric acid Which of the following statements are true? Select all that apply. View Available Hint(s) Benzene is more resistant to temperature change than sulfuric acid More heat is required to raise the temperature of 1 g of water 1C than to raise the temprature of 1 g of ethyl alcohol 1C More heat is required to raise the temperature of 1 g of benzene 1C than to raise the temperature of 1 g of water 1C Sulfuric acid is less resistant to temperature change than water. Water has a high specific heat due to the hydrogen bonding between water molecules Ethyl alcohol likely exhibits more hydrogen bonding than water Water is less resistant to temperature change than ethyl alcohol
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The table shown here lists the molar heats of vaporization for several organic compounds. Use specific examples from this list to illustrate how the heat of vaporization varies with (a) molar mass, (b) molecular shape, (c) molecular polarity, (d) hydrogen-bonding interactions. Explain these comparisons in terms of the nature of the intermolecular forces at work. (You may find it helpful to draw out the structural formula for each compound.) $$ \begin{array}{ll} \hline \text { Compound } & \begin{array}{l} \text { Heat of } \\ \text { Vaporization (kJ/mol) } \end{array} \\ \hline \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{3} & 19.0 \\ \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3} & 27.6 \\ \mathrm{CH}_{3} \mathrm{CHBrCH}_{3} & 31.8 \\ \mathrm{CH}_{3} \mathrm{COCH}_{3} & 32.0 \\ \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{Br} & 33.6 \\ \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH} & 47.3 \\ \hline \end{array} $$

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The table shown here lists the molar heats of vaporization for several organic compounds. Use specific examples from this list to illustrate how the heat of vaporization varies with (a) molar mass, (b) molecular shape, (c) molecular polarity, (d) hydrogen-bonding interactions. Explain these comparisons in terms of the nature of the intermolecular forces at work. (You may find it helpful to draw out the structural formula for each compound.) $$ \begin{array}{ll} \text { Compound } & \begin{array}{l} \text { Heat of Vaporization } \\ \mathbf{( k J / m o l )} \end{array} \\ \hline \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{3} & 19.0 \\ \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3} & 27.6 \\ \mathrm{CH}_{3} \mathrm{CHBrCH}_{3} & 31.8 \\ \mathrm{CH}_{3} \mathrm{COCH}_{3} & 32.0 \\ \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{Br} & 33.6 \\ \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH} & 47.3 \end{array} $$

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Transcript

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00:01 All right, on question 92, we're given a table with six different compounds, which i have drawn out here, and included their heat of vaporizations and their molecular weights.
00:12 And the question asks us to explain really what's happening with the variance in the heat of vaporization.
00:21 With reference to in part a, we're looking at the molar mass, the molecular weight.
00:28 We can think of it as part b.
00:30 Looking at shape.
00:34 In part c, we're looking at polarity.
00:41 And in part d, we're looking at hydrogen bonding.
00:48 So in terms of molecular weight, in general, as we increase the molecular weight with other factors being equal, we usually increase the interim strength of the london dispersion forces.
01:01 And therefore, it's going to be harder to take more energy to separate the liquid.
01:08 Break those intermectar forces and go from a liquid to a gas, which is what we're doing when we're vaporizing here, this delta asia vaporization.
01:15 So the stronger the intermuclear forces, the higher this heat of vaporization.
01:21 But that's with all other things being equal.
01:23 So the two to really want to compare for part a would be these first two.
01:28 They are both just carbon hydrogen chains, straight chains.
01:31 They don't have other atoms in there that can lead to polarity issues.
01:37 So really the only thing involved, the only type of intermeculary forces involved in these first two molecules are london dispersion forces because that they are non -polar molecules.
01:48 So that's the only thing that's going to be holding them together.
01:50 So this is where molecular weight really becomes important, the molar mass.
01:55 As the molar mass increases, going from 44 to 72, our heat of vaporization increases from 19 to 27 .6.
02:05 Because again, the larger this molecule, the greater the molecular weight, the more polarizable it is.
02:12 The more polarizable it is, the stronger the london dispersion forces.
02:16 The stronger the london dispersion forces, the more energy it takes to separate out those molecules from a liquid to a gas, therefore the higher the heat of vaporization.
02:26 In part b, we're looking at shape.
02:31 And shape becomes important in terms of interaction between the molecules.
02:36 Molecules when they're trying to form these intermolecular forces...
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