The tangential velocity of a body in a non-uniform circular motion varies as v = 7t2 – 2v with the radius being equal to 21 m. What is the angular acceleration at t = 2 s in rad/s2? a) 4/3 b) 5/3 c) 4 d) 7/5
Added by Samay S.
Step 1
Step 1: Given the tangential velocity \( v \) as a function of time \( t \): \[ v = 7t^2 - 2v \] Show more…
Show all steps
Close
Your feedback will help us improve your experience
Kajal Raghubanshi and 97 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The tangential velocity in a circular motion change as v = 2t2 – 7 with the radius being equal to 3 m. What is the angular velocity at t = 1 s in rad/s? a) -5/3 b) -2/3 c) 3 d) -3/5
Kajal R.
The radius of a body moving in a circle with constant angular velocity is given by r = 4t2, with respect to time. What is the magnitude of the tangential velocity at t = 2s, if the angular velocity is 7 rad/s? a) 112 b) 113 c) 56 d) 28
The total acceleration of a particle in circular motion is $5 \mathrm{~m} / \mathrm{s}^{2}$. If the speed of the particle decreases at a rate of $3 \mathrm{~m} / \mathrm{s}^{2}$, assuming $r=2 \mathrm{~m}$, the angular speed $\omega$ of the particle relative to the centre of the circle is (a) $1 \mathrm{rad} / \mathrm{s}$ (b) $\sqrt{2} \mathrm{rad} / \mathrm{s}$ (c) $2 \mathrm{rad} / \mathrm{s}$ (d) $2 \sqrt{2} \mathrm{rad} / \mathrm{s}$
Motions in Two and Three Dimensions
Section B
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD