Question

The thermochemical equation for the combustion of ethanol is shown below: C2H5OH(l) + 3O2(g) → 2CO2(g) + 3H2O(g) ΔH = -1234 kJ/mol What is the enthalpy change (ΔH) for the combustion of 3.50 g of ethanol (C2H5OH, molar mass = 46.07 g/mol)? −1.23 × 104 kJ −4.32 × 103 kJ −1.62 × 104 kJ −123 kJ −93.7 kJ

          The thermochemical equation for the combustion of ethanol is shown below:
C2H5OH(l) + 3O2(g) → 2CO2(g) + 3H2O(g) ΔH = -1234 kJ/mol

What is the enthalpy change (ΔH) for the combustion of 3.50 g of ethanol (C2H5OH, molar mass = 46.07 g/mol)?
−1.23 × 104 kJ
−4.32 × 103 kJ
−1.62 × 104 kJ
−123 kJ
−93.7 kJ
        
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Added by David H.

Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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The thermochemical equation for the combustion of ethanol is shown below: C2H5OH(l) + 3O2(g) → 2CO2(g) + 3H2O(g) ΔH = -1234 kJ/mol What is the enthalpy change (ΔH) for the combustion of 3.50 g of ethanol (C2H5OH, molar mass = 46.07 g/mol)? −1.23 × 104 kJ −4.32 × 103 kJ −1.62 × 104 kJ −123 kJ −93.7 kJ
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Transcript

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00:01 Dear students, enthalpy of combustion of ethanol is given minus 1234 kilojoule per mole.
00:07 Since the equation is balanced, this clearly shows that 1 mole of ethanol gives on combustion releases energy 1234 kilojoules.
00:19 Therefore we have to calculate the enthalpy change for the combustion of 3 .5 gram of ethanol.
00:29 Now as for the question, 1 mole of 1.
00:36 Ethanol that is 1 mole means 46 .07 46 .07 gram of ethanol on combustion gives 1234 kilojoules of heat...
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