00:01
Hi, so we are to determine the x component of the electric force exerted on the charge q sub o.
00:09
So let's draw the x, y plane first.
00:14
This is q sub o.
00:16
And then q sub o and q sub 1 have opposite charges.
00:24
So this would attract.
00:29
As for q sub 2 and q sub o, they have both positive charges.
00:38
On negative charges rather, so this would repel.
00:42
We have force here.
00:45
This is exerted by 1 to q of o.
00:49
This is exerted by charge 2 to o.
00:53
Now the x and y components, this is the y component, and we have the x component, and we know that this is 60 degrees, since we have an equidistant triangle here.
01:07
So this is f net force exerted by 1 to 0, be force, net force multiplied by sign.
01:18
Oh, this is cosine, theta, and this would be sign theta.
01:29
For this second force, 60 degrees, and this is f sub 2, 0, a sign of the angle...