Question

The tide height at a beach is modeled by $h(t) = 5 \cos(t) + 5.5$. The height is $h(t)$ which is measured in feet and the time is $t$ measured in hours. When the tide height is 3 feet, what is the cosine of $t$? $\cos(t) = 1$ $\cos(t) = -\frac{1}{2}$ $\cos(t) = \frac{1}{2}$ $\cos(t) = 0$

          The tide height at a beach is modeled by $h(t) = 5 \cos(t) + 5.5$. The height is $h(t)$ which is measured in feet and the time is $t$ measured in hours.
When the tide height is 3 feet, what is the cosine of $t$?
$\cos(t) = 1$
$\cos(t) = -\frac{1}{2}$
$\cos(t) = \frac{1}{2}$
$\cos(t) = 0$

The tide height at a beach is modeled by h(t) = 5 cos(t) + 5.5. The height is h(t) which is measured in feet and the time is t measured in hours.
When the tide height is 3 feet, what is the cosine of t?
cos(t) = 1
cos(t) = -(1)/(2)
cos(t) = (1)/(2)
cos(t) = 0

Added by Mark A.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

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Solved by Expert Daniel Carr

05/20/2022

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The tide height at a beach is modeled by h(t)=5cos(t)+5.5. The height is h(t) which is measured in feet and the time is t measured in hours. When the tide height is 3 feet, what is the cosine of t ? cos(t)=1 cos(t)=-(1)/(2) cos(t)=(1)/(2) cos(t)=0 The tide height at a beach is modeled by ht=5cost+5.5.The height is h(t)which ismeasured in feet and the time is t measured in hours When the tide height is 3 feet, what is the cosine of t? Ocost=1 Ocost=- 12 Ocos= Ocos(t=0