Question

The time (in minutes) between arrivals of customers to a post office is to be modelled by the Exponential distribution with mean 0.390.39. Please give your answers to two decimal places. Part a) What is the probability that the time between consecutive customers is less than 15 seconds? Part b) Find the probability that the time between consecutive customers is between ten and fifteen seconds. Part c) Given that the time between consecutive customers arriving is greater than ten seconds, what is the chance that it is greater than fifteen seconds?

          The time (in minutes) between arrivals of customers to a post
office is to be modelled by the Exponential distribution with
mean 0.390.39. Please give your answers to two decimal
places. 
Part a) 
What is the probability that the time between consecutive customers
is less than 15 seconds? 
Part b) 
Find the probability that the time between consecutive customers is
between ten and fifteen seconds. 
Part c) 
Given that the time between consecutive customers arriving is
greater than ten seconds, what is the chance that it is greater
than fifteen seconds?
        
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Elementary Statistics a Step by Step Approach
Elementary Statistics a Step by Step Approach
Allan G. Bluman 9th Edition
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The time (in minutes) between arrivals of customers to a post office is to be modelled by the Exponential distribution with mean 0.390.39. Please give your answers to two decimal places. Part a) What is the probability that the time between consecutive customers is less than 15 seconds? Part b) Find the probability that the time between consecutive customers is between ten and fifteen seconds. Part c) Given that the time between consecutive customers arriving is greater than ten seconds, what is the chance that it is greater than fifteen seconds?
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Transcript

-
00:01 In the following question, it is given that 1 minus 1 by k squared multiple 100 that is equals to 89%.
00:09 So we will get 1 minus 1 by k square that is equals to 0 .89.
00:16 Therefore 1 by k square that is 0 .11.
00:20 So k square that is 1 by 0 .11.
00:24 So k which is equals to 3.
00:27 Now we have to find the data lies with three...
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