The time needed to complete a final testing in a particular college course is normally distributed with a mean of 79 minutes and a standard deviation of 8 minutes. Answer the following questions. a. What is the probability of completing the test in one hour or less (to 4 decimals)? b. What is the probability that a student will complete the test in more than 60 minutes but less than 75 minutes (to 4 decimals)? c. Assume that the class has 60 students and that the testing period is 90 minutes in length. How many students do you expect will be unable to complete the test in the allotted time (to nearest whole number)?
Added by Jose Miguel M.
Step 1
Given: Mean (μ) = 79 Standard Deviation (σ) = 8 X = 60 Calculate z-score: \[ z = \frac{X - \mu}{\sigma} = \frac{60 - 79}{8} = -2.375 \] ** Show more…
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