The time period of a freely suspended magnet is 4 seconds. If it is broken in length into two equal parts and one part is suspended in the same way, then its time period will be
Added by Sotor S.
Step 1
Given: Initial moment of inertia, \(I_1 = \frac{mL^2}{12}\) After breaking into two equal parts, moment of inertia, \(I_2 = \frac{m(\frac{L}{2})^2}{12} = \frac{mL^2}{48} = \frac{1}{4}I_1\) Show more…
Show all steps
Your feedback will help us improve your experience
Kajal Raghubanshi and 81 other Physics 103 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The time period of a freely suspended magnet is 2 sec. If it is broken in length into two equal parts and one part is suspended in the same way, then its time period will be
Godha R.
The time period of a thin bar magnet in earth’s magnetic field is T. If the magnet is cut into two equal parts perpendicular to its length, the time period of each part in the same field will be
The period of oscillation of a freely suspended bar magnet is $4 s$. If it is cut into two equal parts in length, then the time period of each part will be [a) $4 \mathrm{~s}$ (b) $2 \mathrm{~s}$ (c) $0.5 \mathrm{~s}$ (d) $0.25 \mathrm{~s}$
Magnetostatics
Round 1
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD