00:01
One we have our pca so our pka is equal to 1 .81 your ph is equals to pka when the concentration of the concentration of from a part and the concentration form from b part will be equal your point a represent your pca second is we have the positive one this is the species is formed in point b and basically we have have our o, which this is the species which is formed in point c.
00:37
So ph is equals to pca plus log.
00:44
We have our salt and you need to divide it by the acid.
00:51
So we have pca plus log point c over point b.
01:01
And point c is equals to point b.
01:06
This would be equal to 50.
01:09
So our ph is equal to pca, our subscript is equal to 2, so we have equal to 6 .05.
01:18
So the point c just above ph is equal to 6.
01:22
It makes sense that the point c that represent ph is equal to 6 .05, having a 50 -50 mixture of species, which is the positive 1 and 0.
01:33
For number three, the major molecule is the zero charge species, and we have c is the major above.
01:45
So ph is equal to 6 .05.
01:48
When your ph is above 6 .05, then the major point will be species c.
01:54
And point d represent this one.
01:59
Actually, at ph is equal to pca is equal to 1 .81, so it means it's 50.
02:04
50 -50 mixture of forms a and b.
02:07
Then with increase in ph amount of your point b increases, now when your ph is equal to p -k -a, so the number form of your species a is present, but there is 50 -50 mixture of species b and species c.
02:24
So from point b and onwards.
02:27
So this would be from point b and onwards.
02:29
For question number four, here only one c ooh group is present...