The toroid shown in the figure has a wire carrying a current I= 9.90 Amperes wrapped around it N= 510 times. The inner radius is R1= 17.0cm and outer radius R2= 20.4cm. Cross Sectional View Top View What is the magnitude of the magnetic field along a circle that is halfway between the inner and outer edges of the toroid?
Added by Kathryn A.
Close
Step 1
We know that the magnetic field inside a toroid is given by: B = μ0 * N * I / (2π * r) where μ0 is the permeability of free space, N is the number of turns of wire, I is the current, and r is the distance from the center of the toroid. Show more…
Show all steps
Your feedback will help us improve your experience
Penny Riley and 73 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Narayan H.
Find the magnetic field in the center of a wire semicircle like that shown in the figure, with radius R = 22.0 cm, if the current in the wire is i = 19.0 A.
Prabhu R.
Find the magnetic field in the center of a wire semicircle like that shown in the figure, with radius $R=10.0 \mathrm{~cm},$ if the current in the wire is $i=12.0 \mathrm{~A}$.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD