The total pressure exerted by the oxygen saturated with water vapor is 764 torr at a temperature at which water vapor pressure is 26 torr. Find the partial pressure of the oxygen. 790 torr 738 torr 0.0340 torr 1.99 x 10^4 torr 29.4 torr
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We are given the total pressure of a mixture of oxygen gas and water vapor, which is 764 torr. We are also given the partial pressure of the water vapor, which is 26 torr. We need to find the partial pressure of the oxygen gas in the mixture. Show more…
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A sample of oxygen gas is saturated with water vapor at $27^{\circ} \mathrm{C}$ . The total pressure of the mixture is 772 torr, and the vapor pressure of water is 26.7 torr at $27^{\circ}$ . What is the partial pressure of the oxygen gas?
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A sample of oxygen gas is saturated with water vapor at 27 . C. The total pressure of the mixture is 772 torr, and the vapor pressure of water is 26.7 torr at 27 . $\mathrm{C}$. What is the partial pressure of the oxygen gas?
The vapour pressure of water at $80^{\circ} \mathrm{C}$ is 355 torr. A $100 \mathrm{~mL}$ vessel contained water saturated oxygen at $80^{\circ} \mathrm{C}$, the total gas pressure being. 760 torr. The contents of the vessel were pumped into a $50.0 \mathrm{~mL}$ vessel at the same temperature. What were the partial pressures of oxygen and water vapour, what was the total pressure in the first equilibrated state? Neglect volume of any water which might condense.
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