Question

The triangular loop of wire shown in the drawing carries a current of I = 4.01 A. A uniform magnetic field is directed parallel to side AB of the triangle and has a magnitude of 2.45 T. (a) Find the magnitude of the magnetic force exerted on each side of the triangle. (b) Determine the magnitude of the net force exerted on the triangle.

Name: the triangular loop of wire shown in the drawing carries a current of i 401 a a uniform magnetic field is directed parallel to side ab of the triangle and has a magnitude of 245 t a find the 38966
Uploaded: 2022-06-06T12:58:38-08:00
Duration: 1 min 31 s
Channel: Shaiju T
Description: the triangular loop of wire shown in the drawing carries a current of i 401 a a uniform magnetic field is directed parallel to side ab of the triangle and has a magnitude of 245 t a find the 38966

          The triangular loop of wire shown in the drawing carries a
current of I = 4.01 A. A uniform magnetic field
is directed parallel to side AB of the triangle
and has a magnitude of 2.45 T. (a) Find
the magnitude of the magnetic force exerted on each side of the
triangle. (b) Determine the magnitude of
the net
force exerted on the triangle.

Added by Sara B.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Shaiju T

06/06/2022

Step 1

Given: Current, I = 4.01 A Magnetic field, B = 2.45 T Angle between current and magnetic field, θ = 55 degrees The magnetic force on a current-carrying wire is given by the formula F = I * L * B * sin(θ), where L is the length of the wire. For side AB: Length of Show more…

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The triangular loop of wire shown in the drawing carries a current of I = 4.01 A. A uniform magnetic field is directed parallel to side AB of the triangle and has a magnitude of 2.45 T. (a) Find the magnitude of the magnetic force exerted on each side of the triangle. (b) Determine the magnitude of the net force exerted on the triangle.