The two blocks (m = 16 kg and M = 88 kg) in Fig. 6-38 are not attached to each other. The coefficient of static friction between the blocks is $\mu_{s}=0.38,$ but the surface beneath the larger block is frictionless. What is the minimum magnitude of the horizontal force $\vec{F}$ required to keep the smaller block from slipping down the larger block?

          The two blocks
(m = 16 kg and M = 88 kg) in Fig.
6-38 are not attached to each other.
The coefficient of static friction between the blocks is $\mu_{s}=0.38,$ but the surface beneath the larger block is frictionless. What is the minimum magnitude of the horizontal force $\vec{F}$ required to keep the smaller block from slipping down the larger block?

Added by Rebecca C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Animesh Raj

07/01/2022

Step 1

Step 1: Apply Newton's second law to find the acceleration of the system: \[a = \frac{F}{m + M}\] Show more…

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The two blocks (m = 16 kg and M = 88 kg) in Fig. 6-38 are not attached to each other. The coefficient of static friction between the blocks is $\mu_{s}=0.38,$ but the surface beneath the larger block is frictionless. What is the minimum magnitude of the horizontal force $\vec{F}$ required to keep the smaller block from slipping down the larger block?