00:01
Hello students, in this question two blocks are given let it be a and b.
00:08
The mass of block a is given as 20 kilogram and the mass of block b is given as 10 kilogram and for block a the coefficient of static friction is given as 0 .5 and coefficient of kinetic friction is given as 0 .3.
00:32
Similarly for block b the coefficient of static friction is given as 0 .6 and the coefficient of kinetic friction is given as 0 .4.
00:44
So for the first part of the question now the blocks are at rest.
00:48
In this case we have to compare the frictional force on block a and the frictional force on block b.
00:56
So when the blocks are at rest then if at rest then static friction comes into force.
01:10
So static friction acts on the blocks.
01:20
So therefore we can calculate the frictional force from the formula that is frictional force is equal to mu s into n that is the normal force which is mu s into mg.
01:40
Now let's calculate the frictional force of a which is mu s m1 g here for similarly for block b it is mu s2 m2 g.
01:58
So mu s1 here is 0 .5.
02:01
So 0 .5 into mass is 20 kilogram into g is 9 .8.
02:08
Similarly for block 2 it is 0 .6 into 10 kilogram into g is 9 .8.
02:18
So calculating the forces the frictional force acting on the block a is 98 newton and the frictional force acting on block b is 58 .8 newton...