The two bodies of masses m1 and m2 (m1 > m2) respectively are tied to the ends of a string which passes over a light frictionless pulley. The masses are initially at rest and released. The acceleration of the centre of mass is
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Step 1: Start with the given information that the two bodies have masses \(m_1\) and \(m_2\) where \(m_1 > m_2\), and they are tied to the ends of a string passing over a frictionless pulley. Show more…
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The two bodies of masses $m_{1}$ and $m_{2}\left(m_{1}>m_{2}\right)$ respectively are tied to the ends of a string which passes over a light frictionless pulley. The masses are initially at rest and released. The acceleration of the centre of mass is (a) $\left(\frac{m_{1}-m_{2}}{m_{1}+m_{2}}\right)^{2} g$ (b) $\left(\frac{m_{1}-m_{2}}{m_{1}+m_{2}}\right) g$ (c) $g$ (d) zero
The two bodies of mass $m_{1}$ and respectively are tied to the ends of a massless string, which passes over a light and frietionless pulley. The masses are initially at rest and then released. Then acceleration of the centre of mass of the system is (a) $\left(\frac{m_{1}-m_{2}}{m_{1}+m_{2}}\right)^{2} g$ (b) $\left(\frac{m_{1}-m_{2}}{m_{1}+m_{2}}\right)^{2}$ (c) $g$ (d) zero
Centre of Mass
Round 2
" Two masses m1 and m2 (m1 > m2) are connected by massless flexible and inextensible string passed over massless and frictionless pulley. The acceleration of centre of mass is"
Dharmendra M.
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