2 \, \text{N} \), \( F_2 = 16.0 \, \text{N} \), and \( \theta = 120^\circ \).
\[ F = \sqrt{10.2^2 + 16.0^2 + 2(10.2)(16.0)\cos(120^\circ)} \]
\[ F = \sqrt{104.04 + 256 + 326.4(-0.5)} \]
\[ F = \sqrt{104.04 + 256 - 163.2} \]
\[ F = \sqrt{196.84} \]
\[ F \approx
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