4.8 m 2.2 kg 3.2 kg 1.80 m The two masses that are...

Transcript

00:01 In this question there is a figure given so first i will draw this figure and explain the data given so you can see that in the figure there is a pulley given so consider that this is the pulley mass less pulley and friction less and further the height of this pulley is given with respect to ground that is considered at first in first that is this is a ground so height is given in the figure you can see that 4 .8 meter and further in the figure you can see that this pull is trying to hang two blocks so with the help of rope so consider that this is the rope so this is the first block and this is a second block and the mass are that is for this block mass is given 2 .2 kg and for this another block mass is given that is 3 .2 kg so initially they are at same height so that is from the ground height is given for both blocks that is before releasing that is given height is 1 .80 meter so this data is given and now in the question it is asking that we have to find the height maximum height does the lightest object or i can say that that is lightest blocks reaches after releasing after the system is released so that means system is that is moolly sorry pulley plus two blocks so that means system is released so this is the cushion now my next step is i am answering the given question so here you can see that again i am drawing this figure so and after it i am trying to release the both objects so this is the pulley so you can see that initially both blocks are at 1 .80 meter with respect to ground that means at same height so and the mass is that is this is 2 .2 kg and this is a 3 .2 kg so that means i can say that the light lightest block is lightest object is that is this and this this is a heavier object.

02:52 So now next step is after releasing the system so then it will be act like this that is this is the pulley height is that is given in the the equation that is 4 .8 meter so i can say that after releasing it will become that is that is this lightest block is going to that is having mass that is 2 .2 kg so this lightest is going to upward and this heavier block is going downward so that means having mass that is 3 .2 kg and reaction will be that is downward so this condition is going to happen after releasing so and this height is given for pulley with respect to ground that is 4 .8 meter so now in the question it is that when this heavier block is touching the ground then you can see that this lightest block is covering a maximum height so we have to find that height so consider that at this height it is reaching so so this is the initial condition and now after it covering maximum height that is h capital h so for finding the value of edge here i am drawing a force diagram for this case so you can see that for 2 .2 kg that means lightest block having force that is upward force will be that is tension t will be showed at is tension so that is which is acting in the rope so and a download will be that is its own weight that means multiplied by g so you can that this is going upward with an acceleration that is i am assuming that is a and now i am drawing another force diagram for second block that means heavier block so having a mass that is 3 .2 kg so i can see that weight will be that is acting downward and value will be that is 3 .2g and now here tension will be that is acting upward because you can see that this block is connected with this rope so tension will be in the rope that is from the for with respect to this block that is towards upward so value will be same because rope is same for both blocks so tension will be same and now this every block is going downward with same acceleration that is which i had assumed the that is a so so this is the force diagram now next step is here i am balancing the force that force for both block so after looking the first block the equation will be for that is written as that is 3 .2g minus t is equal to 3 .2 sorry this is the equation for second block so first i am writing the equation for first block so that will be that is t minus 2 .2 g is equal to m .a that means 2 .2 multiplied by a.

06:59 Now after looking the second block force equation will be that is i consider at 3 .2g minus t is equal to 3 .2a.

07:10 So this is a equation 1 and this is an equation number 2.

07:17 Now next step is add equation 1 and equation to both side.

07:26 So that means we have to add the both side of both equation so after adding the left side will be written as that that is that will become that is 3 .2 minus 2 .2 that means 1 that is equal to g so and on the right side after adding it will be written that is 5 .4 a so now next step is i can say that that acceleration a will be equal to g divided by 5 .4 and we know that the value of g that is gravity having a value that is 9 .8 meter per second is squared so divided by 5 .4 so that will be equal to 1 .81 meter per second square so this is the acceleration by which both block are moving so now after getting the value of acceleration next step is i'm using the equation of motion from kinematic so equation is that is written as s is equal to u t plus half a t square so apply this equation sorry apply this equation for for this given figure so you can see that after applying this equation i am trying to find the value of t that means time t so so this time will give the time duration for which this heavier block is touching the ground and this tightest block is taking a maximum height...

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