00:01
The type of household for the u .s.
00:02
Population for a random sample of 411 households from the dove creek community in montana are shown.
00:09
So we have our type of household, married with children, married no children, single parent, and then one person or other.
00:27
And we have observed amounts that i'm going to put in here.
00:31
So the observed amounts for married with children was 93, married no children was 121, single parent was 36, one person was 89, and other was 72.
00:53
Now, the question they ask us is they ask us what sampling distribution will you use for this test.
00:59
So i'm going to use a chi -square test, and they say are all the expected frequencies greater than 5? and they are.
01:07
So we're going to take 411 times 26%, and we get 106 .86.
01:16
For 29%, we get 119 .19.
01:22
For 9%, we get 36 .99, 102 .75, and 45 .21.
01:33
So our null hypothesis is that the proportions match what's expected, which means our alternative hypothesis would be at least one is different.
01:48
So when we do the chi -square test, we know all the frequencies are greater than 5.
01:56
What are the degrees of freedom? so the degree of freedom for this test is 5 minus 1, which would make the degree of freedom 4.
02:04
The critical value for this test is if we are testing at a significance level of 5%, it would be 0 .05 divided by 2 with a degree of freedom of 4, which would be 11 .1433...