00:01
Hi there, so for this problem we're told that the uncertainty delta p sets a lower bound on the average momentum of a particle in the nucleus.
00:12
If a particle's average momentum were to fall below that point, then the uncertainty principle will be violated, since the uncertainty principle is a fundamental law of visits.
00:24
This cannot happen.
00:26
So using that the uncertainty on the momentum delta p is a given number.
00:31
Value of 1 .06 times 10 to the minus 20 kilograms per times second as the minimum momentum of a particle in the nucleus.
00:53
We need to find the minimum kinetic energy of the particle, using that the mass of this particle is 1 .67 times 10, to the minus 27 kilograms.
01:13
Now, with that said, what we need to obtain is the minimum kinetic energy.
01:19
Now, we know that the kinetic energy is defined as 1 divided by 2 times the mass times the uncertainty, well, in this case, the assertity on the speed to the square...