Question

3. The uniform beam shown in figure weighs 500lbs and support a 400N load. Find the Tension in the tie rope and the force of the hinge on the beam. Give your answer in Newton and Pounds. 4. The uniform beam weighs 400N. If the tie rope can support 3500lbs, what is the maximum value the load can be (in Newton)?

          3. The uniform beam shown in figure weighs 500lbs and support a 400N load. Find the Tension in the tie rope and the force of the hinge on the beam. Give your answer in Newton and Pounds.

4. The uniform beam weighs 400N. If the tie rope can support 3500lbs, what is the maximum value the load can be (in Newton)?

Show more…

3. The uniform beam shown in figure weighs 500lbs and support a 400N load. Find the Tension in the tie rope and the force of the hinge on the beam. Give your answer in Newton and Pounds.

4. The uniform beam weighs 400N. If the tie rope can support 3500lbs, what is the maximum value the load can be (in Newton)?

Added by Roberto I.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Paul Gabriel

11/09/2021

Step 1

1 lb is approximately 4.44822 N, so the weight of the beam is 500 lbs * 4.44822 N/lb = 2224.11 N. Show more…

Show all steps

lock

Thanks for your feedback!

The uniform beam shown in figure weighs 500lbs and support a 400N load. Find the Tension in the tie rope and the force of the hinge on the beam. Give your answer in Newton and Pounds. The uniform beam weighs 400N. If the tie rope can support 3500lbs, what is the maximum value the load can be (in Newton)?

Play audio

Feedback

Powered by NumerAI

Paul Gabriel and 79 other subject Physics 101 Mechanics educators are ready to help you.

Ask a new question

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Recommended Videos

Recommended Textbooks

Transcript

00:01 Hi, in this question, we have this diagram.

00:04 We have the uniform beam weighs 500 pounds and then it supports a 400 newton load and find the tension on the rope.

00:15 So first of all, 500 pounds is equal to 226 .8 kilograms.

00:32 So we have the tension, the component of the tension in this direction, which is going to be gotten from this triangle so this is 65 and this end of being the tension so that's called detention t this will be t cost 65 degrees so we can put the mass of the beam which is 226 .8 kilograms so we went to use the torque to solve this the total clockwise talk might we call to the counterclockwise torque so now the time time clock is supplied by the tension so we have t talk is equal to the force times the distance from the center of rotation which is here this is the pivot so we have t plus 65 times 0 .3l is equal to the total clockwise which is 226 .8 times the acceleration into gravity 9 .81 that gives us the force times the distance to the center which is going to be 3 .5l because at the it is exactly half the length of the beam is 0 .5 l plus the 400 newton weight which is at the end of the beam so this is going to be l the length total length of the beam so 400 times l so solving for t to be equal to so the tension and be called to 1 11 ,929 newtons now to find this the force of the hinge on the beam so let's find the force at this point the two forces here the reaction forces.

02:31 So it's called this frh representing the horizontal reaction force and then fvh representing the vertical reaction force.

02:46 So the horizontal reaction force will be the sum of order to be the net force for the horizontal forces and there are no other force...

Ace is your personal tutor. It breaks down any question with clear steps so you can learn.

Start Using Ace

Continue solving this problem

Create a free account to:

View full step-by-step solution
Ask follow-up questions with Ace AI
Save progress and study later