00:01
Hello students, let's do this question.
00:02
Here, mean of the difference is given, that is the value of d bar is equals to 1 .007, then sample size n is equals to 13 is also given, and the value of sample standard deviation or difference of sample standard deviation, yes, is equals to 1 .209 is also given, and we have to perform the test.
00:24
So our null hypothesis h0 becomes mu a is equals to mu b against the alternative hypothesis h1 becomes mu a less than mu b, which is our alternative hypothesis.
00:40
So here, mu a denotes mean number of crashes after the camera and mu b denotes mean number of crashes before the camera.
00:48
So here the value of test statistic becomes test statistic t is equals to d bar upon, s upon square root of n and it follows t with n minus 1 comma alpha degrees of freedom so here level of significance is equal to alpha is equal to 0 .05 is given so our critical value of t that is t n minus 1 12 .0 .05 is equal to 1 .7 at 2 which is our critical value of test statistic and calculated value of test statistic t is equal to 1 .007 divided by 1 .209.
01:24
Divided by square root of 13 is equals to 3 .003 ,2, which is our calculated value of test statistic.
01:33
So from this we observe that calculated t is greater than tabulated tree or critical t...