The v-t graph for the motion of a car as it moves along a straight road is shown. When t = 0, s = 0. Determine the motorcylces position and acceleration at t = 8 seconds and t = 12 seconds v (m/s) v = 1.25t v = 5 5 v = -t + 15 t(s) 4 10 15
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To find the position at t=8 seconds, we need to substitute t=8 into the equation for s(t): s(8) = 0.5(8)^3 + 15(8)^2 + 10(8) s(8) = 0.5(512) + 15(64) + 80 s(8) = 256 + 960 + 80 s(8) = 1296 meters Therefore, the car's position at t=8 seconds is 1296 meters. Show more…
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The $v-t$ graph for the motion of a car as it moves along a straight road is shown. Draw the $s-t$ and $a-t$ graphs. Also determine the average speed and the distance traveled for the 15 -s time interval. When $t=0, s=0$
The $v-t$ graph for the motion of a car as it moves along a straight road is shown. Draw the $s-t$ and $a-t$ graphs. Also determine the average speed and the distance traveled for the 15 -s time interval. When $t=0, s=0$.
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