The value of \( \frac{\left(3+\cot 76^{\circ} \cot 16^{\circ}\right)}{\cot 76^{\circ}+\cot 16^{\circ}} \) is
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The cotangent function has the identity: \(\cot(90^\circ - \theta) = \tan(\theta)\). Thus, \(\cot 76^\circ = \tan 14^\circ\) and \(\cot 16^\circ = \tan 74^\circ\). Show more…
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