Question

The value of the equilibrium constant, K, for the reaction 3 H2(g) + N2(g) ↔ 2 NH3(g) is 4.3x10^-4 at 648 K. Determine the equilibrium concentration of NH3 if the initial concentrations are 0.11 M N2 and 0.04 M H2.

Name: the value of the equilibrium constant k for the reaction 3 h2g n2g 2 nh3g is 43x10 4 at 648 k determine the equilibrium concentration of nh3 if the initial concentrations are 011 m n2 and 00 06622
Uploaded: 2023-07-13T21:44:16-08:00
Duration: 2 min 33 s
Channel: Jennifer Hudspeth
Description: the value of the equilibrium constant k for the reaction 3 h2g n2g 2 nh3g is 43x10 4 at 648 k determine the equilibrium concentration of nh3 if the initial concentrations are 011 m n2 and 00 06622

          The value of the equilibrium constant, K, for the reaction
3 H2(g) + N2(g) ↔ 2 NH3(g)
is 4.3x10^-4 at 648 K. Determine the equilibrium concentration of NH3 if the initial concentrations are 0.11 M N2 and 0.04 M H2.

Added by Melanie C.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Jennifer Hudspeth

07/13/2023

Step 1

Step 1: Write the equilibrium expression for the reaction: K = [NH3]^2 / ([H2]^3 * [N2]) Show more…

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The value of the equilibrium constant, K, for the reaction 3 H2(g) + N2(g) ↔ 2 NH3(g) is 4.3x10^-4 at 648 K. Determine the equilibrium concentration of NH3 if the initial concentrations are 0.11 M N2 and 0.04 M H2.