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Hello students, in this question we are asked to find out the normal boiling point of liquid, that is, p2, we have to find out.
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We are given the vapor pressure of liquid, that is p 1, is equal to 400.
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Wapper pressure of any liquid at normal boiling point is, that is p 2 is 760.
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Sure, we are given the enthalpy of vaporization that is delta h is equal to 45 .34 kilojoule per mole, or it is 45340 joules per because 1 kilojou is equal to 1 ,000 jude.
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Then temperature t1 is given as 69 degrees celsius which is equal to, that is equal to 342 .15 kelvin.
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Because 0 degrees celsius is equal to 273 .15 kelvin.
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So now we will use the flossius clapperon equation that is flossius placeron equation.
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Equation that is long t1 upon t2 is equal to minus delta h upon r 1 upon t1 minus 1 1 t 2 so we will substitute the values here that is long 400 upon 760 is equal to minus 453 4 .0 divided by 8 .314 into 1 .34 .15 minus 1 upon 342 .15 minus 1 upon 2 .02...