00:07
Now this question basically we're giving a table, right, which is shown here, that it gives you basically the data vapor pressure versus temperature for benzene, right? you basically have the close to the collier's colloquium equation which can be reaching this firm, and you have the temperature t here, and you have two coefficients in a b you ask you determine the coefficient from the values given the table.
00:28
Well, that's pretty easy.
00:30
You just need to select two values of t, right, and get the equation with this nb and solve the equation, right? so let's do it.
00:36
So let's pick up two temperatures, right? for example, i'm going to pick up just, for example, the first two temperatures for the simplicity.
00:44
While you'll find that, you know, if you look at the first temperature and then the pressure will be just one, right? and that means you take the logarithm of the pressure, you get zero, right? and you find this to begin by a minus b over.
00:59
Now, t, at the temperature is minus 36 .7, right? so you get 2, 3, 7 .15.
01:06
Right, minus 36 .7, right? and of course, this can be re -reading as 1a minus, so 1 divided by 273 .15, right, and minus 36 .7, and that actually gives me 0 .004b, right? and of course, we can look at the second part, we get another equation.
01:36
Now the left -hand side, we get lower, of 10.
01:40
Now the p in this case is 5, right? so just put 5 here and this will be given by a minus b over a different temperature now.
01:47
That temperature is 19 .6 right.
01:49
So that will give you 2, 3, 715 minus 19 .6 right...