Question

The vapor pressure of water at 100.0 °C is 760 torr. What would be the vapor pressure of water in torr at 135 °C? ?Hvap of water is 40600 J/mol Helpful Notes: • ln (P1/P2) = ln(P1) - ln(P2). • You must use Kelvin, not Celsius, in the equation • To solve for x when ln(x) = y, e^y = x

          The vapor pressure of water at 100.0 °C is 760 torr. What would be the vapor pressure of water in torr at 135 °C? ?Hvap of water is 40600 J/mol

Helpful Notes:

• ln (P1/P2) = ln(P1) - ln(P2).
• You must use Kelvin, not Celsius, in the equation
• To solve for x when ln(x) = y, e^y = x

The vapor pressure of water at 100.0 °C is 760 torr. What would be the vapor pressure of water in torr at 135 °C? ?Hvap of water is 40600 J/mol

Helpful Notes:

• ln (P1/P2) = ln(P1) - ln(P2).
• You must use Kelvin, not Celsius, in the equation
• To solve for x when ln(x) = y, e^y = x

Added by Julia H.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert David Collins

12/08/2021

Step 1

\(T_1 = 135 + 273 = 408 K\) \(T_2 = 100 + 273 = 373 K\) Show more…

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The vapor pressure of water at 100.0 °C is 760 torr. What would be the vapor pressure of water in torr at 135 °C? ΔHvap of water is 40600 J/mol Helpful Notes: • ln (P1/P2) = ln(P1) - ln(P2). • You must use Kelvin, not Celsius, in the equation • To solve for x when ln(x) = y, e^y = x