0:00
Hello.
00:02
So this is a question about the i do gas equation.
00:07
We're going to be finding some number of moles.
00:10
It's going to help us to get a mass.
00:14
So we're going to start up by getting some parameters down.
00:17
So what we have is we have pressure of water vapor.
00:23
The pressure of the water vapor is 23 .76 tall.
00:32
We need to convert that to atm.
00:34
That's one atmosphere.
00:35
So that's going to be.
00:38
Times one atmosphere is 760 tall so that's going to be 0.
00:49
Of course you can see that the toll is going to cancel the toll.
00:53
We're going to go off to the atm so that's going to be 0 .0 -313 atm.
01:04
The volume of the water vapor has been giving us 1 .5 for latest the temperature of the water vapor is 25.
01:16
Degrees celsius.
01:19
This will convert us kelvin so we add 273 and then we have 298 kelvin.
01:30
The gas constant because we are dealing with atm and latest, the gas constant are we're going to be using will be 0 .082 1 liters.
01:46
Atm per kelvin per mole okay so from the i do gas equation pv it was an rt so you can get the number of moles which is pv over rt so what is p p is 0 .0 313 atm 313 313 we got our volume to be 1 .5 our r is 0 .0 821 our temperature is 298 so the number of moles of water vapor that's going to be 0 .00192 mole okay that's going to be the number of moles of water vapor so once we have that we can get the mass because number of moles also equal to mass over the molar mass.
03:05
So we can have the mass to be equal to the number of moles times the molar mass of water vapor.
03:16
So the number of moles is 0 .00 .2 and the molar mass of water vapor is 18 .02 grampe amoe.
03:32
So the mass will be 0 .0...