The vapor pressure of water is 1.0 atm at 373 K, and the enthalpy of vaporization is 40.7 kJ mol-1 . At what temperature will the vapor pressure be 0.697 atm and at what temperature will the vapor pressure be 1.409 atm?
Added by Ellen R.
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We can use the Clausius-Clapeyron equation to relate the vapor pressure, temperature, and enthalpy of vaporization: ln(P2/P1) = -ΔHvap/R * (1/T2 - 1/T1) where P1 and P2 are the initial and final vapor pressures, T1 and T2 are the initial and final temperatures, Show more…
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