The velocity of a 3.2-kg particle is given by v = 3.2t³i + (1.6-3.7t²)j +2.5k, where v is in meters per second and the time t is in seconds.
Determine the linear momentum G of the particle, its magnitude G, and the net force R which acts on the particle when t = 1.2 s.
Answers:
G= ( i+ j+ k) kg m/s
G= kg m/s
R= ( i+ j+ k) N