00:01
In this question, they have given that a basketball is seen to pass upward by a window of 14 meters.
00:07
So what i can say, let's say this is a ball that is thrown below the height of the street that is 14 meter.
00:16
And this is our street.
00:17
And let's say this is the highest point at which the ball is gone.
00:21
So this distance is 14 meter because they have given that ball is thrown below the height of 14 meter.
00:28
And let's say this is y not this is y1 and let's say this height is y2 and according to this the final velocity it means the vertical speed of the bowl it is equal to 16 meter per second so let's say this is v it is equal to 16 meter per second so in the first part of this question we have to answer that what was it initial speed so according to this what can we say in the first part we have to calculate the initial speed.
01:00
So as we know the formula from the three equations of motion, that final speed square minus initial speed square, it is equal to 2, multiply by acceleration due to gravity, multiply by the height, right? now in this case, my final velocity is 16 meters per second.
01:19
From this equation, if i solve for initial speed, so initial speed square will be equal to final speed square minus 2, multiply by g, multiply by height...