The vertices of a square are located at L(-1,1) M(6,1) N(6,8) and I(-1,8) what is the area of the square?
Added by Antonio W.
Step 1
First, we need to find the length of one side of the square. We can do this by using the distance formula between two points. Let's use L and M as our points: d = √[(6 - (-1))^2 + (1 - 1)^2] d = √[7^2 + 0^2] d = √49 d = 7 So, the length of one side of the square Show more…
Show all steps
Your feedback will help us improve your experience
Bradley Duda and 74 other Geometry educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Find the area of the square with vertices at $(1,2),(6,2),(6,7)$ and $(1,7)$
Coordinate Geometry Extended
Coordinate-Geometry Practice
What is the area of the triangle whose three vertices are at the XY coordinates: (4,3), (4,9), and (8,3)? 8 square units 10 square units 24 square units 12 square units 18 square units
Suman K.
Find the area of the triangle having the vertices (-2, 6) , (6, 3) , and (-6,9).
Adi S.
Recommended Textbooks
Geometry A Common Core Curriculum
Geometry
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD