Question

The visible electromagnetic spectrum ranges from about 390 nm (violet) to 760 nm (red). This corresponds to photons with energies from (h = 6.6 × 10^-34 J·s, c = 3 × 10^8 m/s, e = 1.6 × 10^-19 C)..... (a) 1.4 eV to 2.7 eV; (b) 1.6 eV to 3.2 eV; (c) 1.8 eV to 3.5 eV; (d) 1.4 keV to 2.7 keV; (e) 1.6 keV to 3.2 keV; (f) 1.8 keV to 3.5 keV.

Name: the visible electromagnetic spectrum ranges from about 390 nm violet to 760 nm red this corresponds to photons with energies from h 66 10 34 js c 3 108 ms e 16 10 19 c a 14 ev to 27 ev b 16 ev to 32 e
Uploaded: 2021-11-16T00:58:01-08:00
Duration: 1 min 32 s
Channel: Mahipal Kumawat
Description: the visible electromagnetic spectrum ranges from about 390 nm violet to 760 nm red this corresponds to photons with energies from h 66 10 34 js c 3 108 ms e 16 10 19 c a 14 ev to 27 ev b 16 ev to 32 e

          The visible electromagnetic spectrum ranges from about 390 nm (violet) to 760 nm (red). This corresponds to photons with energies from (h = 6.6 × 10^-34 J·s, c = 3 × 10^8 m/s,  e = 1.6 × 10^-19 C).....
(a) 1.4 eV to 2.7 eV;
(b) 1.6 eV to 3.2 eV;
(c) 1.8 eV to 3.5 eV;
(d) 1.4 keV to 2.7 keV;
(e) 1.6 keV to 3.2 keV;
(f) 1.8 keV to 3.5 keV.

Added by Nour J.

Modern Physics

Paul A. Tipler, Ralph A. Llewellyn 6th Edition

Chapter 3

Instant Answer

Solved by Expert Mahipal Kumawat

11/16/2021

Step 1

Given: - Planck's constant, h = 6.6 × 10^-34 J·s - Speed of light, c = 3 × 10^8 m/s - Charge of an electron, e = 1.6 × 10^-19 C - Wavelength, λ1 = 390 nm = 390 × 10^-9 m Use the formula E = hc/λ to calculate the energy: E = (6.6 × 10^-34 J·s * 3 × 10^8 m/s) / Show more…

Show all steps

Thanks for your feedback!

The visible electromagnetic spectrum ranges from about 390 nm (violet) to 760 nm (red). This corresponds to photons with energies from (h = 6.6 × 10^-34 J·s, c = 3 × 10^8 m/s, e = 1.6 × 10^-19 C)..... (a) 1.4 eV to 2.7 eV; (b) 1.6 eV to 3.2 eV; (c) 1.8 eV to 3.5 eV; (d) 1.4 keV to 2.7 keV; (e) 1.6 keV to 3.2 keV; (f) 1.8 keV to 3.5 keV.