The waiting time at an elevator is uniformly distributed between 30 and 300 seconds. Find the mean and standard deviation of the waiting time. Group of answer choices 150 seconds and 6075 (seconds)2 3 minutes and 1.50 minutes 150 seconds and 90 second 2.75 minutes and 1.30 minutes
Added by Kholoud A.
Step 1
Since the waiting time is uniformly distributed between 30 and 300 seconds, the mean can be found by taking the average of the minimum and maximum waiting times: Mean = (30 + 300) / 2 = 330 / 2 = 165 seconds Now, we need to find the variance of the waiting time. Show more…
Show all steps
Close
Your feedback will help us improve your experience
Luis Garcia and 79 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Practice: Group work The waiting time at an elevator is uniformly distributed between 30 and 200 seconds. Find the mean and standard deviation of the waiting time. A) 115 seconds and 49.07 seconds B) 1.15 minutes and 0.4907 minutes C) 1.15 minutes and 24.08333 (minute)^2 D) 115 seconds and 2408.3333 (second)^2
Qudsiya A.
David N.
The time (in minutes) that a randomly selected individual waits for an elevator in an office building has a distribution with a mean of 0.5 and a standard deviation of 0.289. (a) Let X be the sample mean waiting time for a random sample of 50 individuals. What are the mean and standard deviation of the sampling distribution of X? (b) Approximate P(0.45 ≤ X ≤ 0.57).
Adi S.
Recommended Textbooks
Elementary and Intermediate Algebra
Algebra and Trigonometry
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD