Question

The wavelength of the first line of He^ + ion spectral series, whose interval between the extreme lines is 2.725 × 10^6 m^-1 , is : (R = 1.09 × 10^7 m^-1) A. 471.82 nm B. 4718.2 nm C. 1019.37 nm D. 165.14 nm

Name: the wavelength of the first line of he ion spectral series whose interval between the extreme lines is 2725 106 m 1 is r 109 107 m 1 a 47182 nm b 47182 nm c 101937 nm d 16514 nm 30462
Uploaded: 2023-07-05T08:03:27-08:00
Duration: 3 min 7 s
Channel: Sri K
Description: the wavelength of the first line of he ion spectral series whose interval between the extreme lines is 2725 106 m 1 is r 109 107 m 1 a 47182 nm b 47182 nm c 101937 nm d 16514 nm 30462

          The wavelength of the first line of He^ +  ion spectral series, whose interval between the extreme lines is 2.725 × 10^6 m^-1 , is : (R = 1.09 × 10^7 m^-1)
A. 471.82 nm
B. 4718.2 nm
C. 1019.37 nm
D. 165.14 nm

Added by Javier G.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Sri K

07/05/2023

Step 1

We are given the interval between the extreme lines as 2.725 × 10^6 m^-1, which means that: 1/λ1 - 1/λ∞ = 2.725 × 10^6 m^-1 where λ1 is the wavelength of the first line and λ∞ is the wavelength of the last line (i.e., the limit as n approaches infinity). We Show more…

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The wavelength of the first line of He^ + ion spectral series, whose interval between the extreme lines is 2.725 × 10^6 m^-1 , is : (R = 1.09 × 10^7 m^-1) A. 471.82 nm B. 4718.2 nm C. 1019.37 nm D. 165.14 nm