00:01
Assuming a full tank, find the smallest force p.
00:08
We need to consider the moment about the pivot point at the bottom edge of the tank.
00:13
The weight of the water is given by density times g times volume.
00:19
And so we have our 9 .81 times pi r squared h.
00:31
And that would be kiloons per meters cubed.
00:35
Now for tipping, we need the moment about that pivot.
00:38
Point equal to the moment due to the weight of the water.
00:42
So the moment due to our force is p times 2r, set that equal to weight times r.
00:50
So then p is weight divided by 2, which is pi r squared height times 9 .81 over 2 kiloons.
01:01
We don't have the radius or the height, but if you had those, you can plug this in to solve for that.
01:08
Find the smallest coefficient of static friction for b...