The wet feed solid material to a continuous dryer contains 40 wt% water on a wet basis ans is dr

so let's solve this question so in this question we have omega 1 equals to 0 .6 2 11 .9 by 100 m

To solve this question we have to calculate the fraction of atom sites at temperature 1357 which

To solve description we have average atomic rate A average 100 divided by C iron a a plus C .V b

So let's solve this question just as I've searched PA equals to 0 .8 into 7 .384 that equals to

So when solving for soil moisture content for sample two, we can simply plug in the sample two v

Question

The wet feed solid material to a continuous dryer contains \( 40 \mathrm{wt} \% \) water on a wet basis ans is dried to 27 wt \% (wet basis) by a counter-current air flow. The dried solid product leaves at the rate of \( 1050 \mathrm{~kg} / \mathrm{h} \). Fresh air to the system is at \( 32^{\circ} \mathrm{C} \) and has a humidity of \( 0.006 \mathrm{~kg} \) water/kg dry air. The moist air leaves the dryer at \( 40^{\circ} \mathrm{C} \) and humidity of \( 0.025 \mathrm{~kg} \) water/ \( \mathrm{kg} \) dry air. Part of this air is recirculated and mixed with the fresh air before entering the heater (See drawing below). The heated mixed air enter the dryer at \( 65.6^{\circ} \mathrm{C} \) and humidity of \( 0.010 \mathrm{~kg} \) water/kg dry air. The solid enters at \( 32^{\circ} \mathrm{C} \) and leaves at the same temperature \( \left(32^{\circ} \mathrm{C}\right) \). Calculate: (a) the fresh air flow rate in \( \mathbf{k g} \) air/ \( \mathbf{h} \) (not in \( \mathrm{kg} \mathrm{dry} \mathrm{air/h} \) ) (b) the percentage of air recycled (c) the heat added to the heater in \( \mathrm{kW} \) (d) the heat loss from the dryer in \( \mathrm{kW} \) Hint: Wet basis weight percent of water \( =[\mathrm{kg} \) of water / ( \( \mathrm{kg} \) of water \( +\mathrm{kg} \) of dry solid) ] \( 100 \% \) Dry basis weight percent of water \( =[\mathrm{kg} \) of water \( / \mathrm{kg} \) of dry solid ] \( ] 100 \%) \) FIGURE 9.10-4. Process flow for air recirculation in drying.

          The wet feed solid material to a continuous dryer contains \( 40 \mathrm{wt} \% \) water on a wet basis ans is dried to 27 wt \% (wet basis) by a counter-current air flow. The dried solid product leaves at the rate of \( 1050 \mathrm{~kg} / \mathrm{h} \). Fresh air to the system is at \( 32^{\circ} \mathrm{C} \) and has a humidity of \( 0.006 \mathrm{~kg} \) water/kg dry air. The moist air leaves the dryer at \( 40^{\circ} \mathrm{C} \) and humidity of \( 0.025 \mathrm{~kg} \) water/ \( \mathrm{kg} \) dry air. Part of this air is recirculated and mixed with the fresh air before entering the heater (See drawing below). The heated mixed air enter the dryer at \( 65.6^{\circ} \mathrm{C} \) and humidity of \( 0.010 \mathrm{~kg} \) water/kg dry air. The solid enters at \( 32^{\circ} \mathrm{C} \) and leaves at the same temperature \( \left(32^{\circ} \mathrm{C}\right) \). Calculate:
(a) the fresh air flow rate in \( \mathbf{k g} \) air/ \( \mathbf{h} \) (not in \( \mathrm{kg} \mathrm{dry} \mathrm{air/h} \) )
(b) the percentage of air recycled
(c) the heat added to the heater in \( \mathrm{kW} \)
(d) the heat loss from the dryer in \( \mathrm{kW} \)
Hint:
Wet basis weight percent of water \( =[\mathrm{kg} \) of water / ( \( \mathrm{kg} \) of water \( +\mathrm{kg} \) of dry solid) ] \( 100 \% \)
Dry basis weight percent of water \( =[\mathrm{kg} \) of water \( / \mathrm{kg} \) of dry solid ] \( ] 100 \%) \)
FIGURE 9.10-4. Process flow for air recirculation in drying.

The wet feed solid material to a continuous dryer contains 40 wt% water on a wet basis ans is dried to 27 wt % (wet basis) by a counter-current air flow. The dried solid product leaves at the rate of 1050 kg / h. Fresh air to the system is at 32^∘C and has a humidity of 0.006 kg water/kg dry air. The moist air leaves the dryer at 40^∘C and humidity of 0.025 kg water/ kg dry air. Part of this air is recirculated and mixed with the fresh air before entering the heater (See drawing below). The heated mixed air enter the dryer at 65.6^∘C and humidity of 0.010 kg water/kg dry air. The solid enters at 32^∘C and leaves at the same temperature (32^∘C). Calculate:
(a) the fresh air flow rate in 𝐤 𝐠 air/ 𝐡 (not in kgdryair/h )
(b) the percentage of air recycled
(c) the heat added to the heater in kW
(d) the heat loss from the dryer in kW
Hint:
Wet basis weight percent of water =[kg of water / ( kg of water +kg of dry solid) ] 100 %
Dry basis weight percent of water =[kg of water / kg of dry solid ] ] 100 %)
FIGURE 9.10-4. Process flow for air recirculation in drying.

Added by Samet K.

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