00:01
This problem says the width of a rectangle is 5 feet longer than 2 times its length and its area is 18.
00:06
If we use l to represent the length of the rectangle, find an expression that represents the width.
00:11
And if our width is told to be 5 feet longer than 2 times the length, we will define w in terms of l.
00:17
So 5 feet longer than 2 times the length would increase 2 times the length plus 5.
00:23
So 2l plus 5 represents our width here.
00:26
And then for the equation to represent the area of the rectangle, we would show length times width, we're going to show width replaced with his expression that's in terms of length.
00:34
So we'll have l times 2l plus 5.
00:38
And remember, that's a version of length times width.
00:41
So that would give us our area of 18 squared feet or 18 feet squared.
00:45
And now we can use this equation to solve for the length and the width of the rectangle.
00:49
So we'll distribute l to 2l and to 5 to give us 2l squared plus 5l still equal to 18.
00:57
And then we're going to subtract 18 over.
01:00
So that we can attempt to factor this.
01:01
So that gives us 2l squared plus 5l minus 18 equal to 0...