the work function of potassium is 230 ev uv light of wavelength 3000 a and intensity 2 wm 2 is i

Name: the work function of potassium is 230 ev uv light of wavelength 3000 a and intensity 2 wm 2 is incident on the potassium surface 1 determine the maximum kinetic energy of the photo electrons 92474
Uploaded: 2022-03-19T05:18:44-08:00
Duration: 3 min 32 s
Channel: Urvashi Arora
Description: the work function of potassium is 230 ev uv light of wavelength 3000 a and intensity 2 wm 2 is incident on the potassium surface 1 determine the maximum kinetic energy of the photo electrons 92474

Question

The work function of potassium is 2.30 eV. UV light of wavelength 3000 Å and intensity 2 Wm -2 is incident on the potassium surface. 1) Determine the maximum kinetic energy of the photo electrons. 2) If 40% of incident photons produce photo electrons, how many electrons are emitted per second if the area of the potassium surface is 2 cm2 ?

          The work function of potassium is 2.30 eV. UV light of wavelength 3000 Å and intensity 2 Wm -2 is incident on the potassium surface. 1) Determine the maximum kinetic energy of the photo electrons. 2) If 40% of incident photons produce photo electrons, how many electrons are emitted per second if the area of the potassium surface is 2 cm2 ?

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University Physics with Modern Physics

Hugh D. Young 14th Edition

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03/19/2022

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The work function of potassium is 2.30 eV. UV light of wavelength 3000 Å and intensity 2 Wm -2 is incident on the potassium surface. 1) Determine the maximum kinetic energy of the photo electrons. 2) If 40% of incident photons produce photo electrons, how many electrons are emitted per second if the area of the potassium surface is 2 cm2 ?