00:01
Okay, so the way i'm seeing this problem is we have the lows at 330 and then again at 330.
00:09
So that's a 12 hour period.
00:12
And so, yeah, as they're asking some of these questions, i guess i should also put that this y value is 60.
00:25
This y value up here is 80.
00:27
So if you want the midline, i'm sorry, i said that wrong, then this value is 100.
00:38
So the midline would be the average of those two, 100 plus 60 divided by 2, which takes me to 80.
00:46
So that first bullet point, i'm assuming that that's what they wanted.
00:52
I would go ahead and mark that one true.
00:54
With the period being 12, a lot of times we find that b value by doing 2 pi divided by the period, which reduces to pi over 6.
01:05
So again, i would mark that one true.
01:08
I just mentioned how the period equaling 24 is wrong because the period was 12.
01:15
So that would be false.
01:17
And then this next one, i'd probably write out an equation and i'm just going to make it so it's at the, like 0 is 330.
01:28
330 equals 0.
01:30
So then i could create an equation.
01:33
So y equals the amplitude from 80 to 100 would be 20 plus, sorry, let's just make it a negative cosine...