There are 7 women and 5 men in a department. A committee of five people is to be selected. How many different ways can the committee be selected if there must be 3 women and 2 men?
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This can be done in C(7,3) ways, which is equal to 7! / (3! * (7-3)!) = 7! / (3! * 4!) = (7 * 6 * 5) / (3 * 2 * 1) = 35 ways. Show more…
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