There are 8 people in a room. I pick 3 people to be on my team. The order in which I pick my team members does not matter. How many different teams could I make? Group of answer choices: 56
Added by Dale B.
Step 1
This can be calculated using the combination formula: C(n, k) = n! / (k!(n-k)!) In this case, C(8, 3) = 8! / (3!(8-3)!) = 8! / (3!5!) = (8*7*6) / (3*2*1) = 56 Show more…
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